用 grep 匹配已有檔案中的多個字元，比如 48 ，用排序符號，輸入命令如下 grep 48 filename ，提示 grep Invalid collation charact

1樓：jesse

[.48.] by default is not defined to be treated as an atom in bracket expression.

You need to define [.48.] in locale before using it.

Reference from(Regular Expressions):

A collating symbol is a collating element enclosed within bracket-period ( "[." and ".]" ) delimiters.

Collating elements are defined as described in Collation Order.

Conforming

collating symbols when it is necessary to distinguish them from

a list of the individual characters that make up the multi-character

collating element. For example, if the string "ch" is

a collating element defined using the line:

collating-element from ""

in the locale definition, the expression "[[.ch.]]" shall be treated as an RE containing the collating symbol

'ch', while "[ch]" shall be treated as an RE matching 'c' or 'h'. Collating symbols are

recognized only inside bracket expressions. If the string is not a collating element in the current locale, the expression is

invalid.

2樓：依雲

regex(7) 裡有對於此語法的說明：

Within a bracket expression, a collating element (a character, a multicharacter sequence that collates as if it were a single character, or a collating-sequence name for either) enclosed in "[." and ".]" stands for the sequence of characters of that collating element.

但是「48」不是乙個字元，不是乙個被作為單個字元排序的多字元，也不是乙個排序序列名。

用 grep 匹配已有檔案中的多個字元，比如 48 ，用排序符號，輸入命令如下 grep 48 filename ，提示 grep Invalid collation charact

你們對於秒倒隊友賽後說「匹配而已」有什麼看法？

甲骨文的冊字能說明商朝已有簡冊麼？

用正規表示式匹配非括號內的資料

其他用戶還看了：

用 grep 匹配已有檔案中的多個字元，比如 48 ，用排序符號，輸入命令如下 grep 48 filename ，提示 grep Invalid collation charact

你們對於秒倒隊友賽後說 「匹配而已」有什麼看法？

甲骨文的冊字能說明商朝已有簡冊麼？

用正規表示式匹配非括號內的資料

其他用戶還看了：

你們對於秒倒隊友賽後說「匹配而已」有什麼看法？